If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4b^2+12b-7=0
a = 4; b = 12; c = -7;
Δ = b2-4ac
Δ = 122-4·4·(-7)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-16}{2*4}=\frac{-28}{8} =-3+1/2 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+16}{2*4}=\frac{4}{8} =1/2 $
| 4z^2+32z+60=0 | | -14-18n=-20n+12 | | 12-(x-4)=6+x | | (34x+5)/6=76 | | 2x+65=10 | | 3x+456787654x23456=65 | | a|5=1|2(a-3) | | 2x+4+(5x+17)+(6x+6)=180 | | 2x+4+5x+17+6x+6=180 | | -(3t-5)=9-3t | | 3(n-10)=-30+3n | | 15/8=x/80 | | 7-3x=6x-20 | | 18-m=20 | | 110/90=x/100 | | -4(2-x)=4/5(x+10) | | 2x-5(x+4)=4+x | | x-107=10(2x+3)-23 | | 27b+27=6b+3(9+7b) | | -2(x+5)+16=15=3x | | 8x+14+10x+10=180 | | 6v+2=6v-2 | | 2x^2+4x-273=0 | | -5=5-3x/4 | | 4b=11b | | -6=-2(x+3)+2x | | w-9.8=5.4 | | 7.8x=312 | | (z+4)^2+12=0 | | w-1.8=3.79 | | 3^(m)=9 | | 8x+14=10x+10 |